Find the margin of error for the given confidence level and values of $x$ and $n$. $x = 111 , n = 194$, confidence level $99 \%$
A) 0.428
B) 0.572
C) r0.036
D) 0.093

Question

Quizplus · Accepted Answer

The margin of error is calculated using the formula for a proportion: $ ME = Z \times \sqrt{\frac{p(1-p)}{n}} $, where $ p = \frac{x}{n} $ and $ Z $ is the Z-score for the confidence level. For 99% confidence, $ Z \approx 2.576 $. Here, $ p = \frac{111}{194} \approx 0.572 $. Plugging in the values, the margin of error is approximately 0.093.

Find the Margin of Error for the Given Confidence Level xxx

Find the Margin of Error for the Given Confidence Level $x$