On a TV game show, a contestant is shown 8 products from a grocery store and is asked to choose the three least-expensive items in the set. The three chosen items need not be
In any particular order. In how many ways can the contestant choose the three items?
A) 336
B) 6720
C) 6
D) 56

Question

Quizplus · Accepted Answer

The number of ways to choose 3 items out of 8 is calculated using combinations (since the order does not matter). The formula for combinations is C(n, k) = n! / [k!(n-k)!], where n is the total number of items to choose from, and k is the number of items to choose. Here, n=8 and k=3, so the calculation is C(8, 3) = 8! / [3!(8-3)!] = 8! / (3!5!) = (8*7*6) / (3*2*1) = 56.

On a TV Game Show, a Contestant Is Shown 8