If there are 6 means to be compared, then how many possible different comparisons (such as $\bar { X } _ { 2 }$ compared to $\bar { X } _ { 3 }$ ) are there altogether?
A) 15
B) 30
C) 6
D) 36

Question

Quizplus · Accepted Answer

The number of possible different comparisons between 6 means can be calculated using the combination formula $C(n, k) = \frac{n!}{k!(n-k)!}$, where $n$ is the total number of items (6 means in this case) and $k$ is the number of items to choose at a time (2 for a comparison). Thus, $C(6, 2) = \frac{6!}{2!(6-2)!} = 15$.

If There Are 6 Means to Be Compared, Then How Xˉ2\bar { X } _ { 2 }Xˉ2​

If There Are 6 Means to Be Compared, Then How $\bar { X } _ { 2 }$