Use the given information to find the P-value. Also, use a 0.05 significance level and state the conclusion about the null hypothesis (reject the null hypothesis or fail to reject the null hypothesis).
-$\text { With } \mathrm { H } _ { 1 } : \mathrm { p }

Question

Use the given information to find the P-value. Also, use a 0.05 significance level and state the conclusion about the null hypothesis (reject the null hypothesis or fail to reject the null hypothesis).
-$\text { With } \mathrm { H } _ { 1 } : \mathrm { p } < 1 / 5 \text {, the test statistic is } \mathrm { z } = - 1.93 \text {. }$
A) 0.9732; fail to reject the null hypothesis
B) 0.0268; reject the null hypothesis
C) 0.0268; fail to reject the null hypothesis
D) 0.0536; fail to reject the null hypothesis

Quizplus · Accepted Answer

The P-value for a left-tailed test with z = -1.93 is 0.0268. Since 0.0268 < 0.05, we reject the null hypothesis.

Use the Given Information to Find the P-Value With H1:p<1/5, the test statistic is z=−1.93. \text { With } \mathrm { H } _ { 1 } : \mathrm { p } < 1 / 5 \text {, the test statistic is } \mathrm { z } = - 1.93 \text {. } With H1​:p<1/5, the test statistic is z=−1.93.

Use the Given Information to Find the P-Value $\text { With } \mathrm { H } _ { 1 } : \mathrm { p } < 1 / 5 \text {, the test statistic is } \mathrm { z } = - 1.93 \text {. }$