Find the value of the test statistic z using $z = \frac { \hat { p } - p } { \sqrt { \frac { p q } { n } } }$
-The claim is that the proportion of accidental deaths of the elderly attributable to residential falls is more than 0.10, and the sample statistics include n = 800 deaths of the elderly with 15% of them attributable to residential falls.
A) $3.96$
B) $4.71$
C) $- 3.96$
D) $- 4.71$

Question

Find the value of the test statistic z using $z = \frac { \hat { p } - p } { \sqrt { \frac { p q } { n } } }$
-The claim is that the proportion of accidental deaths of the elderly attributable to residential falls is more than 0.10, and the sample statistics include n = 800 deaths of the elderly with 15% of them attributable to residential falls. 
A) $3.96$
B) $4.71$
C) $- 3.96$
D) $- 4.71$

Quizplus · Accepted Answer

The Answer of Find the value of the test statistic z using $z = \frac { \hat { p } - p } { \sqrt { \frac { p q } { n } } }$
-The claim is that the proportion of accidental deaths of the elderly attributable to residential falls is more than 0.10, and the sample statistics include n = 800 deaths of the elderly with 15% of them attributable to residential falls. 
A) $3.96$
B) $4.71$
C) $- 3.96$
D) $- 4.71$

Find the Value of the Test Statistic Z Using z=p^−ppqnz = \frac { \hat { p } - p } { \sqrt { \frac { p q } { n } } }z=npq​​p^​−p​

Find the Value of the Test Statistic Z Using $z = \frac { \hat { p } - p } { \sqrt { \frac { p q } { n } } }$