Use the confidence level and sample data to find a confidence interval for estimating the population µ. Round your answer to the same number of decimal places as the sample mean.
-A random sample of 136 full-grown lobsters had a mean weight of 22 ounces and a standard deviation of 3.2 ounces. Construct a 98% confidence interval for the population mean µ.
A) $22 \mathrm { oz }

Question

Use the confidence level and sample data to find a confidence interval for estimating the population µ. Round your answer to the same number of decimal places as the sample mean.
-A random sample of 136 full-grown lobsters had a mean weight of 22 ounces and a standard deviation of 3.2 ounces. Construct a 98% confidence interval for the population mean µ. 
A) $22 \mathrm { oz } < \mu < 24 \mathrm { oz }$
B) $21 \mathrm { oz } < \mu < 23 \mathrm { oz }$
C) $20 \mathrm { oz } < \mu < 22 \mathrm { oz }$
D) $21 \mathrm { oz } < \mu < 24 \mathrm { oz }$

Quizplus · Accepted Answer

The 98% confidence interval is calculated using the formula: mean ± (critical value * standard error). The critical value for 98% confidence with a large sample size is approximately 2.33. The standard error is the standard deviation divided by the square root of the sample size. Thus, the interval is 22 ± (2.33 * (3.2/√136)), which results in approximately 21 to 23 ounces.

Use the Confidence Level and Sample Data to Find a Confidence