Scores on an English test are normally distributed with a mean of 37.4 and a standard deviation of 7.9. Find the score that separates the top 59% from the bottom 41%
A) 42.1
B) 35.6
C) 39.2
D) 32.7

Question

Quizplus · Accepted Answer

To find the score that separates the top 59% from the bottom 41%, we need to find the z-score that corresponds to the 41st percentile. Using a standard normal distribution table or calculator, the z-score for the 41st percentile is approximately -0.23. Using the formula: score = mean + (z-score * standard deviation), we get: 37.4 + (-0.23 * 7.9) ≈ 35.6.

Scores on an English Test Are Normally Distributed with a Mean