Find the mean of the given probability distribution.
-$\begin{array}{c|c}
\mathrm{x} & \mathrm{P}(\mathrm{x}) \
\hline 0 & 0.23 \
1 & 0.20 \
2 & 0.37 \
3 & 0.06 \
4 & 0.14
\end{array}$

A) $\mu = 1.81$
B) $\mu = 1.68$
C) $\mu = 1.58$
D) $\mu = 1.91$

Question

Find the mean of the given probability distribution.
-$\begin{array}{c|c}
\mathrm{x} & \mathrm{P}(\mathrm{x}) \
\hline 0 & 0.23 \
1 & 0.20 \
2 & 0.37 \
3 & 0.06 \
4 & 0.14
\end{array}$

A) $\mu = 1.81$
B) $\mu = 1.68$
C) $\mu = 1.58$
D) $\mu = 1.91$

Quizplus · Accepted Answer

The mean of a probability distribution is calculated as $\mu = \sum [x \cdot P(x)]$. Here, $\mu = (0 \cdot 0.23) + (1 \cdot 0.20) + (2 \cdot 0.37) + (3 \cdot 0.06) + (4 \cdot 0.14) = 1.68$.

Find the Mean of the Given Probability Distribution xP(x)00.2310.2020.3730.0640.14\begin{array}{c|c}\mathrm{x} & \mathrm{P}(\mathrm{x}) \\\hline 0 & 0.23 \\1 & 0.20 \\2 & 0.37 \\3 & 0.06 \\4 & 0.14\end{array}x01234​P(x)0.230.200.370.060.14​​

Find the Mean of the Given Probability Distribution $\begin{array}{c|c}\mathrm{x} & \mathrm{P}(\mathrm{x}) \\\hline 0 & 0.23 \\1 & 0.20 \\2 & 0.37 \\3 & 0.06 \\4 & 0.14\end{array}$