Assume that a researcher randomly selects 14 newborn babies and counts the number of girls selected, x. The probabilities corresponding to the 14 possible values of x are summarized in the given table. Answer the question using
the table. $$\begin{array}{l}
\text {\quad\quad\quad\quad\quad\quad\quad\quad\quad Probabilities of Girls }\
\begin{array} { c | c | c | c | c | c }
x ( \text { girls } ) & P ( x ) & x \text { (girls) } & P ( x ) & x ( \text { girls } ) & P ( x ) \
\hline 0 & 0.000 & 5 & 0.122 & 10 & 0.061 \
1 & 0.001 & 6 & 0.183 & 11 & 0.022 \
2 & 0.006 & 7 & 0.209 & 12 & 0.006 \
3 & 0.022 & 8 & 0.183 & 13 & 0.001 \
4 & 0.061 & 9 & 0.122 & 14 & 0.000
\end{array}
\end{array}$$
-Find the probability of selecting 2 or more girls.
A) 0.999
B) 0.001
C) 0.994
D) 0.006

Question

Assume that a researcher randomly selects 14 newborn babies and counts the number of girls selected, x. The probabilities corresponding to the 14 possible values of x are summarized in the given table. Answer the question using
the table. $$\begin{array}{l}
\text {\quad\quad\quad\quad\quad\quad\quad\quad\quad Probabilities of Girls }\
\begin{array} { c | c | c | c | c | c } 
x ( \text { girls } ) & P ( x ) & x \text { (girls) } & P ( x ) & x ( \text { girls } ) & P ( x ) \
\hline 0 & 0.000 & 5 & 0.122 & 10 & 0.061 \
1 & 0.001 & 6 & 0.183 & 11 & 0.022 \
2 & 0.006 & 7 & 0.209 & 12 & 0.006 \
3 & 0.022 & 8 & 0.183 & 13 & 0.001 \
4 & 0.061 & 9 & 0.122 & 14 & 0.000
\end{array}
\end{array}$$
-Find the probability of selecting 2 or more girls.
A) 0.999
B) 0.001
C) 0.994
D) 0.006

Quizplus · Accepted Answer

The probability of selecting 2 or more girls is 1 minus the probability of selecting fewer than 2 girls (0 or 1 girl). P(x ≥ 2) = 1 - (P(0) + P(1)) = 1 - (0.000 + 0.001) = 0.999.

Assume That a Researcher Randomly Selects 14 Newborn Babies and Counts