A tourist in France wants to visit 7 different cities. If the route is randomly selected, what is the probability that she will visit the cities in alphabetical order?
A) $\frac { 1 } { 7 }$

B) $\frac { 1 } { 49 }$

C) $\frac { 1 } { 5040 }$

D) 5040

Question

A tourist in France wants to visit 7 different cities. If the route is randomly selected, what is the probability that she will visit the cities in alphabetical order? 
A) $\frac { 1 } { 7 }$

B) $\frac { 1 } { 49 }$

C) $\frac { 1 } { 5040 }$

D) 5040

Quizplus · Accepted Answer

There are 7! (5040) possible ways to arrange 7 cities. Only 1 of these arrangements is in alphabetical order, so the probability is $\frac{1}{5040}$.

A Tourist in France Wants to Visit 7 Different Cities 17\frac { 1 } { 7 }71​

A Tourist in France Wants to Visit 7 Different Cities $\frac { 1 } { 7 }$