Find the standard deviation for the given sample data. Round your answer to one more decimal place than is present in the original data.
-Listed below are the amounts of time (in months) that the employees of a restaurant have been working at the restaurant.
$$\begin{array} { l l l l l l l l l l }
2 & 3 & 5 & 12 & 23 & 31 & 69 & 86 & 101 & 122
\end{array}$$
A) 43.9 months
B) 42.8 months
C) 46.4 months
D) 45.1 months

Question

Find the standard deviation for the given sample data. Round your answer to one more decimal place than is present in the original data.
-Listed below are the amounts of time (in months) that the employees of a restaurant have been working at the restaurant.
 $$\begin{array} { l l l l l l l l l l } 
2 & 3 & 5 & 12 & 23 & 31 & 69 & 86 & 101 & 122
\end{array}$$
A) 43.9 months
B) 42.8 months
C) 46.4 months
D) 45.1 months

Quizplus · Accepted Answer

The standard deviation is a measure of how spread out the data is. The larger the standard deviation, the more spread out the data is. In this case, the standard deviation is 45.1 months. This means that the data is spread out over a range of 45.1 months.

Find the Standard Deviation for the Given Sample Data 2351223316986101122\begin{array} { l l l l l l l l l l } 2 & 3 & 5 & 12 & 23 & 31 & 69 & 86 & 101 & 122\end{array}2​3​5​12​23​31​69​86​101​122​

Find the Standard Deviation for the Given Sample Data $\begin{array} { l l l l l l l l l l } 2 & 3 & 5 & 12 & 23 & 31 & 69 & 86 & 101 & 122\end{array}$