What is the gravitational force acting on a 59-kg person due to another 59-kg person standing 2.0 m away? We can model each person as a small sphere. $\left( G = 6.67 \times 10 ^ { - 11 } \mathrm {~N} \cdot \mathrm { m } ^ { 2 } / \mathrm { kg } ^ { 2 } \right)$

Question

What is the gravitational force acting on a 59-kg person due to another 59-kg person standing  2.0 m away? We can model each person as a small sphere. $\left( G = 6.67 \times 10 ^ { - 11 } \mathrm {~N} \cdot \mathrm { m } ^ { 2 } / \mathrm { kg } ^ { 2 } \right)$

Quizplus · Accepted Answer

The gravitational force between two masses can be calculated using Newton's law of universal gravitation: $F = G \frac{m_1 m_2}{r^2}$, where $G = 6.67 \times 10^{-11} \, \text{N} \cdot \text{m}^2/\text{kg}^2$, $m_1 = 59 \, \text{kg}$, $m_2 = 59 \, \text{kg}$, and $r = 2.0 \, \text{m}$. Plugging these values into the formula gives $F = 6.67 \times 10^{-11} \times \frac{59 \times 59}{2.0^2} = 5.8 \times 10^{-8} \, \text{N}$.

What Is the Gravitational Force Acting on a 59-Kg Person (G=6.67×10−11 N⋅m2/kg2)\left( G = 6.67 \times 10 ^ { - 11 } \mathrm {~N} \cdot \mathrm { m } ^ { 2 } / \mathrm { kg } ^ { 2 } \right)(G=6.67×10−11 N⋅m2/kg2)

What Is the Gravitational Force Acting on a 59-Kg Person $\left( G = 6.67 \times 10 ^ { - 11 } \mathrm {~N} \cdot \mathrm { m } ^ { 2 } / \mathrm { kg } ^ { 2 } \right)$