As a 70-kg person stands at the seashore gazing at the tides (which are caused by the Moon), how Iarge is the gravitational force on that person due to the Moon? The mass of the Moon is 7.35 x $10 ^ { 22 } \mathrm {~kg}$ the distance to the Moon is $3.82 \times 10 ^ { 8 } \mathrm {~m}$ and $G = 6.67 \times 10 ^ { - 11 } \mathrm {~N} \cdot \mathrm { m } ^ { 2 } / \mathrm { kg } ^ { 2 } .$

Question

As a 70-kg person stands at the seashore gazing at the tides (which are caused by the Moon), how Iarge is the gravitational force on that person due to the Moon? The mass of the Moon is  7.35 x $10 ^ { 22 } \mathrm {~kg}$ the distance to the Moon is $3.82 \times 10 ^ { 8 } \mathrm {~m}$ and $G = 6.67 \times 10 ^ { - 11 } \mathrm {~N} \cdot \mathrm { m } ^ { 2 } / \mathrm { kg } ^ { 2 } .$

Quizplus · Accepted Answer

The Answer of As a 70-kg person stands at the seashore gazing at the tides (which are caused by the Moon), how Iarge is the gravitational force on that person due to the Moon? The mass of the Moon is  7.35 x $10 ^ { 22 } \mathrm {~kg}$ the distance to the Moon is $3.82 \times 10 ^ { 8 } \mathrm {~m}$ and $G = 6.67 \times 10 ^ { - 11 } \mathrm {~N} \cdot \mathrm { m } ^ { 2 } / \mathrm { kg } ^ { 2 } .$

As a 70-Kg Person Stands at the Seashore Gazing at the Tides