At a distance of 14,000 km from the center of Planet Z-99, the acceleration due to gravity is 32 $\mathrm { m } / \mathrm { s } ^ { 2 }$ What is the acceleration due to gravity at a point 28,000 km from the center of this planet?

Question

At a distance of  14,000 km from the center of Planet Z-99, the acceleration due to gravity is 32 $\mathrm { m } / \mathrm { s } ^ { 2 }$ What is the acceleration due to gravity at a point  28,000 km from the center of this planet?

Quizplus · Accepted Answer

Acceleration due to gravity is inversely proportional to the square of the distance from the center of the planet. So, if the distance is doubled, the acceleration due to gravity will be reduced to one-fourth of its original value. Therefore, the acceleration due to gravity at a point 28,000 km from the center of the planet will be 32 m/s^2 / 4 = 8 m/s^2.

At a Distance of 14,000 Km from the Center m/s2\mathrm { m } / \mathrm { s } ^ { 2 }m/s2

At a Distance of 14,000 Km from the Center $\mathrm { m } / \mathrm { s } ^ { 2 }$