A large telescope of mass 8410 \mathrm{~kg} is in a circular orbit around the earth, making one revolution every 927 minutes. What is the magnitude of the gravitational force exerted on the satellite by the earth? $\left( G = 6.67 \times 10 ^ { - 11 } \mathrm {~N} \cdot \mathrm { m } ^ { 2 } / \mathrm { kg }^ 2 , M _ { \text {earth } } = 6.0 \times 10 ^ { 24 } \mathrm {~kg} \right)$

Question

A large telescope of mass  8410 \mathrm{~kg}  is in a circular orbit around the earth, making one revolution every 927 minutes. What is the magnitude of the gravitational force exerted on the satellite by the earth? $\left( G = 6.67 \times 10 ^ { - 11 } \mathrm {~N} \cdot \mathrm { m } ^ { 2 } / \mathrm { kg }^ 2 , M _ { \text {earth } } = 6.0 \times 10 ^ { 24 } \mathrm {~kg} \right)$

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The Answer of A large telescope of mass  8410 \mathrm{~kg}  is in a circular orbit around the earth, making one revolution every 927 minutes. What is the magnitude of the gravitational force exerted on the satellite by the earth? $\left( G = 6.67 \times 10 ^ { - 11 } \mathrm {~N} \cdot \mathrm { m } ^ { 2 } / \mathrm { kg }^ 2 , M _ { \text {earth } } = 6.0 \times 10 ^ { 24 } \mathrm {~kg} \right)$

A Large Telescope of Mass 8410 \Mathrm{~kg} Is