A certain aircraft has a mass of 300,000 kg. At a certain instant during its landing, its speed is 27.0 m/s. If the braking force is a constant 445,000 N, what is the speed of the airplane 10.0 s later?
A) 10.0 m/s
B) 14.0 m/s
C) 18.0 m/s
D) 12.2 m/s
E) 20.0 m/s

Question

Quizplus · Accepted Answer

Explanation:The acceleration of the airplane is:$$a = \frac{F}{m} = \frac{445,000 N}{300,000 kg} = 1.48 m/s^2$$The speed of the airplane 10.0 s later is:$$v = u + at = 27.0 m/s + (1.48 m/s^2)(10.0 s) = 41.8 m/s$$

A Certain Aircraft Has a Mass of 300,000 Kg