The atom ${ } _ { 87 } ^ { 223 } \mathrm { Fr }$ decays to ${ } _ { 88 } ^ { 223 } \mathrm { Ra }$ by emitting what kind of nuclear radiation?

Name: The atom ${ } _ { 87 } ^ { 223 } \mathrm { Fr }$ decays to ${ } _ { 88 } ^ { 223 } \mathrm { Ra }$ by emitting what kind of nuclear radiation?
Brand: Quizplus
Rating: 4.9 (51 reviews)

Question

Quizplus · Accepted Answer

The decay from ${ } _ { 87 } ^ { 223 } \mathrm { Fr }$ to ${ } _ { 88 } ^ { 223 } \mathrm { Ra }$ involves an increase in the atomic number by 1, which indicates the emission of a beta-minus particle (electron).

The Atom 87223Fr{ } _ { 87 } ^ { 223 } \mathrm { Fr }87223​Fr

The Atom ${ } _ { 87 } ^ { 223 } \mathrm { Fr }$