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Radium-226 Decays into Radon-222 Plus an Alpha Particle 24He:4.002603u{ } _ { 2 } ^ { 4 } \mathrm { He } : \quad 4.002603 \mathrm { u }

Question 86

Multiple Choice

Radium-226 decays into radon-222 plus an alpha particle. The relevant masses are 24He:4.002603u{ } _ { 2 } ^ { 4 } \mathrm { He } : \quad 4.002603 \mathrm { u }
86222 Rn: 222.017570u88226 Ra: 226.025402u\begin{array} { l l } { } _ { 86 } ^ { 222 } \text { Rn: } & 222.017570 u \\ { } _ { 88 } ^ { 226 } \text { Ra: } & 226.025402 u \end{array}
How much energy is released in this process? (1u=931.5MeV/c2) \left( 1 \mathrm { u } = 931.5 \mathrm { MeV } / \mathrm { c } ^ { 2 } \right)


A) 4.87MeV4.87 \mathrm { MeV }
B) 5.39MeV5.39 \mathrm { MeV }
C) 3.76MeV3.76 \mathrm { MeV }
D) 5.05MeV5.05 \mathrm { MeV }
E) 4.24MeV4.24 \mathrm { MeV }

Correct Answer:

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