When a Stationary Plutonium-239 Nucleus Decays into a Uranium-235 Nucleus $5.24 \mathrm { MeV }$

When a stationary plutonium-239 nucleus decays into a uranium-235 nucleus plus an alpha particle, the energy released in the process is $5.24 \mathrm { MeV }$ . The following masses are known:
${ } _ { 2 } ^ { 4 } \mathrm { He } : \quad 4.002603 \mathrm { u }$
${ } _ { 92 } ^ { 235 } \mathrm { U } : \quad 235.043924 \mathrm { u }$
What is the kinetic energy of the ${ } _ { 92 } ^ { 235 } \mathrm { U }$ nucleus? $\left( 1 \mathrm { u } = 931.5 \mathrm { MeV } / \mathrm { c } ^ { 2 } \right)$

A) $0.0877 \mathrm { MeV }$
B) $0.0863 \mathrm { MeV }$
C) $0.0829 \mathrm { MeV }$
D) $0.0852 \mathrm { MeV }$
E) $0.0837 \mathrm { MeV }$