Neodymium ${ } _ { 60 } ^ { 144 } \mathrm { Nd }$

Neodymium ${ } _ { 60 } ^ { 144 } \mathrm { Nd }$ is an isotope that undergoes alpha decay. What isotope is the product of this decay?

A) ${ } _ { 59 } ^ { 140 } \mathrm { Pr }$
B) ${ } _ { 58 } ^ { 140 } \mathrm { Ce }$
C) ${ } _ { 62 } ^ { 142 } \mathrm { Sm }$
D) ${ } _ { 56 } ^ { 142 } \mathrm { Ba }$
E) ${ } _ { 64 } ^ { 146 } \mathrm { Gd }$