In a room where g = 9.81 m/s², a hockey puck slides off the edge of a platform with an initial velocity of 28.0 m/s horizontally. The height of the platform above the ground is 2.00 m. What is
The speed of the puck just before it hits the ground? The air resistance is negligibly small.
A) 28.7 m/s
B) 6.26 m/s
C) 28.0 m/s
D) 48.2 m/s
E) 26.3 m/s

Question

Quizplus · Accepted Answer

The speed of the puck just before it hits the ground can be found using the Pythagorean theorem, combining the initial horizontal velocity and the final vertical velocity. The horizontal velocity remains constant at 28.0 m/s because there is no air resistance. The final vertical velocity can be calculated using the formula $v = \sqrt{2gh}$, where $g = 9.81 \, m/s^2$ and $h = 2.00 \, m$. Plugging in the values, we get $v = \sqrt{2 \times 9.81 \times 2.00} = \sqrt{39.24} \approx 6.26 \, m/s$. The total speed just before hitting the ground is then $\sqrt{28.0^2 + 6.26^2} \approx 28.7 \, m/s$.

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