If an electron is determined to be at $x = 2.000 \mathrm {~cm} \pm 0.0010 \mathrm {~cm}$, what is the minimum uncertainty in the $x$ component of its velocity? (melectron $= 9.11 \times 10 ^ { - 31 } \mathrm {~kg} , h = 6.626 \times$ $10 - 34 \mathrm {~J} \cdot \mathrm { s }$ )

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The Answer of If an electron is determined to be at $x = 2.000 \mathrm {~cm} \pm 0.0010 \mathrm {~cm}$, what is the minimum uncertainty in the $x$ component of its velocity? (melectron $= 9.11 \times 10 ^ { - 31 } \mathrm {~kg} , h = 6.626 \times$ $10 - 34 \mathrm {~J} \cdot \mathrm { s }$ )

If an Electron Is Determined to Be At x=2.000 cm±0.0010 cmx = 2.000 \mathrm {~cm} \pm 0.0010 \mathrm {~cm}x=2.000 cm±0.0010 cm

If an Electron Is Determined to Be At $x = 2.000 \mathrm {~cm} \pm 0.0010 \mathrm {~cm}$