An Electron Is Trapped in a Quantum Well That Is $48.6 \mathrm {~nm}$

An electron is trapped in a quantum well that is $48.6 \mathrm {~nm}$ wide. Calculate the minimum uncertainty in its velocity. $\left( h = 6.626 \times 10 ^ { - 34 } \mathrm {~J} \cdot \mathrm { s } , m _ { \text {electron } } = 9.11 \times 10 ^ { - 31 } \mathrm {~kg} \right)$

A) $3.34 \times 10 ^ { 4 } \mathrm {~m} / \mathrm { s }$
B) $1.01 \times 10 ^ { 3 } \mathrm {~m} / \mathrm { s }$
C) $1.79 \times 10 ^ { 4 } \mathrm {~m} / \mathrm { s }$
D) $2.38 \times 10 ^ { 3 } \mathrm {~m} / \mathrm { s }$
E) $7.49 \times 10 ^ { 3 } \mathrm {~m} / \mathrm { s }$