An x-ray tube accelerates electrons through a potential difference of $50.0 \mathrm { kV }$. If an electron in the beam suddenly give up its energy in a collision, what is the shortest wavelength x-ray it could produce? $\left( c = 3.00 \times 10 ^ { 8 } \mathrm {~m} / \mathrm { s } , h = 6.626 \times 10 ^ { - 34 } \mathrm {~J} \cdot \mathrm { s } , e = 1.60 \times 10 ^ { - 19 } \mathrm { C } \right)$

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The Answer of An x-ray tube accelerates electrons through a potential difference of $50.0 \mathrm { kV }$. If an electron in the beam suddenly give up its energy in a collision, what is the shortest wavelength x-ray it could produce? $\left( c = 3.00 \times 10 ^ { 8 } \mathrm {~m} / \mathrm { s } , h = 6.626 \times 10 ^ { - 34 } \mathrm {~J} \cdot \mathrm { s } , e = 1.60 \times 10 ^ { - 19 } \mathrm { C } \right)$

An X-Ray Tube Accelerates Electrons Through a Potential Difference Of 50.0