What is the wavelength of a $6.32 - \mathrm { eV }$ photon? $\left( c = 3.00 \times 10 ^ { 8 } \mathrm {~m} / \mathrm { s } , h = 6.626 \times 10 ^ { - 34 } \mathrm {~J} \cdot \mathrm { s } , 1 \mathrm { eV } = 1.60 \right.$ $\times 10 ^ { - 19 } \mathrm {~J}$ )
A) $216 \mathrm {~nm}$
B) $197 \mathrm {~nm}$
C) $167 \mathrm {~nm}$
D) $234 \mathrm {~nm}$

Question

Quizplus · Accepted Answer

The wavelength of a photon can be calculated using the formula $\lambda = \frac{hc}{E}$, where $h$ is Planck's constant, $c$ is the speed of light, and $E$ is the energy of the photon. First, convert the energy from eV to Joules: $6.32 \, \text{eV} \times 1.60 \times 10^{-19} \, \text{J/eV} = 1.0112 \times 10^{-18} \, \text{J}$. Then, calculate the wavelength: $\lambda = \frac{6.626 \times 10^{-34} \, \text{J} \cdot \text{s} \times 3.00 \times 10^8 \, \text{m/s}}{1.0112 \times 10^{-18} \, \text{J}} \approx 1.97 \times 10^{-7} \, \text{m} = 197 \, \text{nm}$.

What Is the Wavelength of A 6.32−eV6.32 - \mathrm { eV }6.32−eV

What Is the Wavelength of A $6.32 - \mathrm { eV }$