When light of wavelength $350 \mathrm {~nm}$ is incident on a metal surface, the stopping potential of the photoelectrons is measured to be $0.500 \mathrm {~V}$. What is the work function of this metal? $\left( c = 3.00 \times 10 ^ { 8 } \right.$ $\mathrm { m } / \mathrm { s } , h = 6.626 \times 10 ^ { - 34 } \mathrm {~J} \cdot \mathrm { s } , 1 \mathrm { eV } = 1.60 \times 10 ^ { - 19 } \mathrm {~J}$ )
A) $3.54 \mathrm { eV }$
B) $4.12 \mathrm { eV }$
C) $3.05 \mathrm { eV }$
D) $0.500 \mathrm { eV }$

Question

Quizplus · Accepted Answer

The energy of the incident photons is calculated using $E = \frac{hc}{\lambda}$. Substituting the given values, $E = \frac{6.626 \times 10^{-34} \times 3.00 \times 10^8}{350 \times 10^{-9}}$ J, which converts to approximately $3.54 \, \text{eV}$. The work function $\phi$ is given by $\phi = E - eV_0$, where $eV_0 = 0.500 \, \text{eV}$. Thus, $\phi = 3.54 - 0.500 = 3.05 \, \text{eV}$.

When Light of Wavelength 350 nm350 \mathrm {~nm}350 nm Is Incident on a Metal Surface, the Stopping Potential of a Metal

When Light of Wavelength $350 \mathrm {~nm}$ Is Incident on a Metal Surface, the Stopping Potential of a Metal