Radio astronomers often study the radiation emitted by a hydrogen atom from a transition between the two hyperfine levels associated with the ground state. This radiation has a wavelength of $21 \mathrm {~cm}$ . What is the energy difference between the hyperfine levels? $( 1 \mathrm { eV } = 1.60 \times$ 10<sup>-19 </sup>J)
A) $5.9 \times 10 ^ { - 6 } \mathrm { eV }$
B) $4.7 \times 10 ^ { - 25 } \mathrm {~J}$
C) $5.9 \times 10 ^ { - 25 } \mathrm {~J}$
D) $1.7 \times 10 ^ { - 24 } \mathrm {~J}$

Question

Radio astronomers often study the radiation emitted by a hydrogen atom from a transition between the two hyperfine levels associated with the ground state. This radiation has a wavelength of

21 \mathrm {~cm}

. What is the energy difference between the hyperfine levels?

( 1 \mathrm { eV } = 1.60 \times

10<sup>-19 </sup>J)
A)

5.9 \times 10 ^ { - 6 } \mathrm { eV }

B)

4.7 \times 10 ^ { - 25 } \mathrm {~J}

C)

5.9 \times 10 ^ { - 25 } \mathrm {~J}

D)

1.7 \times 10 ^ { - 24 } \mathrm {~J}

Quizplus · Accepted Answer

The Answer of Radio astronomers often study the radiation emitted by a hydrogen atom from a transition between the two hyperfine levels associated with the ground state. This radiation has a wavelength of $21 \mathrm {~cm}$. What is the energy difference between the hyperfine levels? $( 1 \mathrm { eV } = 1.60 \times$ 10^-19J) A) $5.9 \times 10 ^ { - 6 } \mathrm { eV }$ B) $4.7 \times 10 ^ { - 25 } \mathrm {~J}$ C) $5.9 \times 10 ^ { - 25 } \mathrm {~J}$ D) $1.7 \times 10 ^ { - 24 } \mathrm {~J}$

Radio Astronomers Often Study the Radiation Emitted by a Hydrogen 21 cm21 \mathrm {~cm}21 cm

Radio Astronomers Often Study the Radiation Emitted by a Hydrogen $21 \mathrm {~cm}$