During a reaction, a reactant loses $4.8 \times 10 ^ { - 28 } \mathrm {~kg}$ of mass. How many joules of energy are released? $\left( c = 3.0 \times 10 ^ { 8 } \mathrm {~m} / \mathrm { s } \right)$
A) $1.6 \times 10 - 36 \mathrm {~J}$
B) $4.3 \times 10 ^ { - 11 } \mathrm {~J}$
C) $5.3 \times 10 ^ { - 45 } \mathrm {~J}$
D) $1.4 \times 10 ^ { - 19 } \mathrm {~J}$

Question

Quizplus · Accepted Answer

The energy released can be calculated using Einstein's mass-energy equivalence formula $E = mc^2$. Substituting the given values, $E = (4.8 \times 10^{-28} \, \text{kg}) \times (3.0 \times 10^8 \, \text{m/s})^2 = 4.3 \times 10^{-11} \, \text{J}$.

During a Reaction, a Reactant Loses 4.8×10−28 kg4.8 \times 10 ^ { - 28 } \mathrm {~kg}4.8×10−28 kg

During a Reaction, a Reactant Loses $4.8 \times 10 ^ { - 28 } \mathrm {~kg}$