Light of intensity S0 that is polarized horizontally passes through three ideal polarizers. The first and third are horizontal, but the second one is oriented at 0.39270 rad to the horizontal. In terms of
S0, the intensity of the light that passes through the set of polarizers is closest to which one of the
Following choices?

Question

Quizplus · Accepted Answer

The intensity after the first polarizer remains S0. After the second polarizer, the intensity is S0 * cos^2(0.39270). After the third polarizer, the intensity remains the same as the second because it is aligned horizontally. Calculating gives approximately 0.729 S0.

Light of Intensity S0 That Is Polarized Horizontally Passes Through