Light having a wavelength in vacuum of $600 \mathrm {~nm}$ enters a liquid of refractive index $2.0$. In this liquid, what is the wavelength of the light? $\left( c = 3.0 \times 10 ^ { 8 } \mathrm {~m} / \mathrm { s } \right)$

Question

Quizplus · Accepted Answer

The wavelength of light in a medium is given by the formula $\lambda' = \frac{\lambda}{n}$, where $\lambda$ is the wavelength in vacuum and $n$ is the refractive index of the medium. Substituting $\lambda = 600 \, \text{nm}$ and $n = 2.0$, we get $\lambda' = \frac{600 \, \text{nm}}{2.0} = 300 \, \text{nm}$.

Light Having a Wavelength in Vacuum Of 600 nm600 \mathrm {~nm}600 nm Enters a Liquid of Refractive Index

Light Having a Wavelength in Vacuum Of $600 \mathrm {~nm}$ Enters a Liquid of Refractive Index