Coherent light of wavelength $540 \mathrm {~nm}$ passes through a pair of thin slits that are $3.4 \times 10 ^ { - 5 } \mathrm {~m}$ apart. At what angle away from the centerline does the second bright fringe occur?

Question

Quizplus · Accepted Answer

The angle for the second bright fringe in a double-slit experiment is found using the formula $d \sin \theta = m\lambda$, where $d$ is the distance between the slits, $\lambda$ is the wavelength of the light, and $m$ is the order number of the fringe (for the second bright fringe, $m = 2$). Solving for $\theta$, we get $\theta = \sin^{-1} \left(\frac{m\lambda}{d}\right) = \sin^{-1} \left(\frac{2 \times 540 \times 10^{-9}}{3.4 \times 10^{-5}}\right) \approx 1.8^\circ$.

Coherent Light of Wavelength 540 nm540 \mathrm {~nm}540 nm Passes Through a Pair of Thin Slits That Are

Coherent Light of Wavelength $540 \mathrm {~nm}$ Passes Through a Pair of Thin Slits That Are