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The Maximum Magnetic Energy Density of a Sinusoidal Electromagnetic Wave 8.95×105 J/m38.95 \times 10 ^ { - 5 } \mathrm {~J} / \mathrm { m } ^ { 3 }

Question 28

Multiple Choice

The maximum magnetic energy density of a sinusoidal electromagnetic wave is 8.95×105 J/m38.95 \times 10 ^ { - 5 } \mathrm {~J} / \mathrm { m } ^ { 3 } . What is the amplitude of the magnetic field component of this wave? (c=3.00×108 m/s,μ0=4π×\left( c = 3.00 \times 10 ^ { 8 } \mathrm {~m} / \mathrm { s } , \mu _ { 0 } = 4 \pi \times \right. 107 Tm/A,ε0=8.85×1012C2/Nm210 ^ { - 7 } \mathrm {~T} \cdot \mathrm { m } / \mathrm { A } , \varepsilon _ { 0 } = 8.85 \times 10 ^ { - 12 } \mathrm { C } ^ { 2 } / \mathrm { N } \cdot \mathrm { m } ^ { 2 } )


A) 12.0μT12.0 \mu \mathrm { T }
B) 13.0μT13.0 \mu \mathrm { T }
C) 14.0μT14.0 \mu \mathrm { T }
D) 16.0μT16.0 \mu \mathrm { T }
E) 15.0μT15.0 \mu \mathrm { T }

Correct Answer:

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