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An Electron Moves with a Speed Of 3.0×104 m/s3.0 \times 104 \mathrm {~m} / \mathrm { s }

Question 83

Multiple Choice

An electron moves with a speed of 3.0×104 m/s3.0 \times 104 \mathrm {~m} / \mathrm { s } perpendicular to a uniform magnetic field of 0.400.40 T. What is the magnitude of the magnetic force on the electron? (e=1.60×1019C) \left( e = 1.60 \times 10 ^ { - 19 } \mathrm { C } \right)


A) 4.8×1014 N4.8 \times 10 ^ { - 14 } \mathrm {~N}
B) 0 N0 \mathrm {~N}
C) 2.2×1024 N2.2 \times 10 - 24 \mathrm {~N}
D) 5×1020 N5 \times 10 - 20 \mathrm {~N}
E) 1.9×1015 N1.9 \times 10 - 15 \mathrm {~N}

Correct Answer:

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