A 2.0-m straight wire carrying a current of 0.60 A is oriented parallel to a uniform magnetic field of 0.50 T. What is the magnitude of the magnetic force on it?

Question

Quizplus · Accepted Answer

The magnetic force on a current-carrying wire is given by F = ILB sin(θ), where I is the current, L is the length of the wire, B is the magnetic field strength, and θ is the angle between the wire and the magnetic field. Since the wire is parallel to the magnetic field, θ = 0 degrees, making sin(θ) = 0. Therefore, the force is zero.

A 20-M Straight Wire Carrying a Current of 0