What is the force per meter on a straight wire carrying $5.0 \mathrm {~A}$ when it is placed in a magnetic field of $0.020 \mathrm {~T}$ so that the wire makes an angle of $27 ^ { \circ }$ with respect to the magnetic field lines.

Question

Quizplus · Accepted Answer

The force per meter on a straight wire in a magnetic field is given by $F/L = BIl \sin \theta$, where $B$ is the magnetic field strength, $I$ is the current, $L$ is the length of the wire, and $\theta$ is the angle between the wire and the magnetic field. Substituting the given values, $F/L = 0.020 \times 5.0 \times \sin(27^\circ) = 0.045 \, \mathrm{N/m}$.

What Is the Force Per Meter on a Straight Wire 5.0 A5.0 \mathrm {~A}5.0 A

What Is the Force Per Meter on a Straight Wire $5.0 \mathrm {~A}$