A jet plane is launched from a catapult on an aircraft carrier. In 2.0 s it reaches a speed of 42 m/s at the end of the catapult. Assuming the acceleration is constant, how far did it travel during those
2)0 s?
A) 24 m
B) 42 m
C) 16 m
D) 84 m

Question

Quizplus · Accepted Answer

Using the formula for distance with constant acceleration, $d = \frac{1}{2}at^2$, and knowing $v = at$, we find $a = \frac{v}{t} = \frac{42 \, \text{m/s}}{2 \, \text{s}} = 21 \, \text{m/s}^2$. Substituting into the distance formula gives $d = \frac{1}{2} \times 21 \, \text{m/s}^2 \times (2 \, \text{s})^2 = 42 \, \text{m}$.

A Jet Plane Is Launched from a Catapult on an Aircraft