An object is moving in a straight line with constant acceleration. Initially it is traveling at 16 m/s. Three seconds later it is traveling at 10 m/s. How far does it move during this time?
A) 48 m
B) 57 m
C) 30 m
D) 39 m

Question

An object is moving in a straight line with constant acceleration. Initially it is traveling at  16 m/s. Three seconds later it is traveling at  10 m/s. How far does it move during this time?
A)  48 m
B)  57 m
C)  30 m
D)  39 m

Quizplus · Accepted Answer

To find the distance traveled, we first calculate the acceleration using the formula $a = \frac{\Delta v}{\Delta t}$, where $\Delta v = v_f - v_i = 10\,m/s - 16\,m/s = -6\,m/s$ and $\Delta t = 3\,s$. Thus, $a = \frac{-6\,m/s}{3\,s} = -2\,m/s^2$. The distance traveled can be found using the formula $s = v_i t + \frac{1}{2} a t^2$, where $v_i = 16\,m/s$, $a = -2\,m/s^2$, and $t = 3\,s$. Substituting these values, we get $s = 16\,m/s \times 3\,s + \frac{1}{2} \times -2\,m/s^2 \times (3\,s)^2 = 48\,m - 9\,m = 39\,m$.

An Object Is Moving in a Straight Line with Constant