A ball is thrown upward at a velocity of 19.6 m/s. What is its velocity after 3.0 s, assuming negligible air resistance?
A) 19.6 m/s downward
B) 0 m/s
C) 9.8 m/s upward
D) 9.8 m/s downward

Question

Quizplus · Accepted Answer

The velocity of the ball after 3.0 s can be calculated using the formula v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration (due to gravity, which is -9.8 m/s^2, indicating a downward acceleration), and t is the time. Substituting the given values: v = 19.6 m/s + (-9.8 m/s^2)(3.0 s) = 19.6 m/s - 29.4 m/s = -9.8 m/s. The negative sign indicates the direction is downward, so the velocity is 9.8 m/s downward.

A Ball Is Thrown Upward at a Velocity of 19