When 5.0 A at 110 V flows in the primary of an ideal transformer, how many amps at 24 V can flow in the secondary?
A) 5.0 A
B) 1.1 A
C) 4.6 A
D) 23 A

Question

Quizplus · Accepted Answer

The power in the primary coil equals the power in the secondary coil for an ideal transformer. Power can be calculated as P = IV. For the primary coil, P = 110V * 5.0A = 550W. To find the current in the secondary coil, rearrange the power equation to I = P/V, so I = 550W / 24V = 22.92A, which rounds to 23A.

When 50 a at 110 V Flows in the Primary of of an Ideal