The primary coil of an ideal transformer has 600 turns and its secondary coil has 150 turns. If the current in the primary coil is 2 A, what is the current in its secondary coil?
A) 4 A
B) 1/2 A
C) 2 A
D) 1/4 A
E) 8 A

Question

Quizplus · Accepted Answer

The current in the secondary coil can be found using the transformer equation $I_1/I_2 = N_2/N_1$, where $I_1$ and $I_2$ are the currents in the primary and secondary coils, respectively, and $N_1$ and $N_2$ are the number of turns in the primary and secondary coils, respectively. Given $N_1 = 600$, $N_2 = 150$, and $I_1 = 2$ A, solving for $I_2$ gives $I_2 = 8$ A.

The Primary Coil of an Ideal Transformer Has 600 Turns