Two taut strings of identical mass per unit length are stretched with the same tension with their ends fixed, but one string is 0.330 cm longer than the other. Waves on these strings propagate at
34)0 m/s.The fundamental frequency of the shorter string is 258 Hz. What is the beat frequency
When each string is vibrating at its fundamental frequency?
A) 11.3 Hz
B) 12.3 Hz
C) 9.00 Hz
D) 12.0 Hz
E) 12.7 Hz

Question

Quizplus · Accepted Answer

The beat frequency is the difference in the fundamental frequencies of the two strings. The fundamental frequency is given by $ f = \frac{v}{2L} $. Since the wave speed $ v $ is the same, the frequency difference is due to the length difference. Calculate the frequency of the longer string and subtract from 258 Hz to find the beat frequency.

Two Taut Strings of Identical Mass Per Unit Length Are