The position of an object that is oscillating on a spring is given by the equation x = (17.4 cm) cos[(5.46 s-1)t]. What is the angular frequency for this motion?
A) 0.869 rad/s
B) 2.34 rad/s
C) 17.4 rad/s
D) 0.183 rad/s
E) 5.46 rad/s

Question

Quizplus · Accepted Answer

The angular frequency for oscillatory motion is given directly by the coefficient of $t$ in the cosine function of the position equation, which in this case is $5.46 \, \text{s}^{-1}$, corresponding to $5.46 \, \text{rad/s}$.

The Position of an Object That Is Oscillating on a Spring