The primary coil of an ideal transformer has 100 turns and its secondary coil has 400 turns. If the ac voltage applied to the primary coil is $120 \mathrm {~V}$, what voltage is present in its secondary coil?
A) $400 \mathrm {~V}$
B) $30 \mathrm {~V}$
C) $100 \mathrm {~V}$
D) $480 \mathrm {~V}$
E) $70 \mathrm {~V}$

Question

Quizplus · Accepted Answer

The voltage in the secondary coil of a transformer is determined by the turns ratio. The formula is $ V_s = V_p \times \frac{N_s}{N_p} $. Here, $ V_p = 120 \mathrm{~V} $, $ N_p = 100 $, and $ N_s = 400 $. So, $ V_s = 120 \times \frac{400}{100} = 480 \mathrm{~V} $.

The Primary Coil of an Ideal Transformer Has 100 Turns 120 V120 \mathrm {~V}120 V

The Primary Coil of an Ideal Transformer Has 100 Turns $120 \mathrm {~V}$