The current through a $50 - \Omega$ resistor is $I = ( 0.80 \mathrm {~A} ) \sin ( 240 t )$. What are (a) the current amplitude and (b) the rms current?

Name: The current through a $50 - \Omega$ resistor is $I = ( 0.80 \mathrm {~A} ) \sin ( 240 t )$. What are (a) the current amplitude and (b) the rms current?
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The Answer of The current through a $50 - \Omega$ resistor is $I = ( 0.80 \mathrm {~A} ) \sin ( 240 t )$. What are (a) the current amplitude and (b) the rms current?

The Current Through A 50−Ω50 - \Omega50−Ω Resistor Is I=(0.80 A)sin⁡(240t)I = ( 0.80 \mathrm {~A} ) \sin ( 240 t )I=(0.80 A)sin(240t)

The Current Through A $50 - \Omega$ Resistor Is $I = ( 0.80 \mathrm {~A} ) \sin ( 240 t )$