A $5.0 - \mu \mathrm { F }$, a $14 - \mu \mathrm { F }$, and a $21 - \mu \mathrm { F }$ capacitor are connected in parallel. How much capacitance would a single capacitor need to have to replace the three capacitors?
A) $21 \mu \mathrm { F }$
B) $14 \mu \mathrm { F }$
C) $5.0 \mu \mathrm { F }$
D) $40 \mu \mathrm { F }$

Question

Quizplus · Accepted Answer

When capacitors are connected in parallel, their capacitances add up. Therefore, the total capacitance is $5.0 \mu \mathrm{F} + 14 \mu \mathrm{F} + 21 \mu \mathrm{F} = 40 \mu \mathrm{F}$.

A 5.0−μF5.0 - \mu \mathrm { F }5.0−μF , A 14−μF14 - \mu \mathrm { F }14−μF

A $5.0 - \mu \mathrm { F }$ , A $14 - \mu \mathrm { F }$