Two 4.0- $\Omega$ resistors are connected in parallel, and this combination is connected in series with $3.0$ $\Omega$. What is the equivalent resistance of this system?
A) $5.0 \Omega$
B) $11 \Omega$
C) $7.0 \Omega$
D) $1.2 \Omega$

Question

Quizplus · Accepted Answer

The equivalent resistance of two 4.0-Ω resistors in parallel is $R_{parallel} = \frac{1}{\frac{1}{4} + \frac{1}{4}} = 2.0 \Omega$. When this is connected in series with a 3.0-Ω resistor, the total equivalent resistance is $R_{total} = R_{parallel} + 3.0 \Omega = 2.0 \Omega + 3.0 \Omega = 5.0 \Omega$.

Two 40- Ω\OmegaΩ Resistors Are Connected in Parallel, and This Combination Is Connected

Two 40- $\Omega$ Resistors Are Connected in Parallel, and This Combination Is Connected