For the circuit shown in the figure, $V = 20 \mathrm {~V} , C = 10 \mu \mathrm { F } , R = 0.80 \mathrm { M } \Omega$, and the battery is ideal. Initially the switch $\mathrm { S }$ is open and the capacitor is uncharged. The switch is then closed at time $t =$ $0.00 \mathrm {~s}$. What is the potential difference across the resistor $20 \mathrm {~s}$ after closing the switch?

A) $2.3 \mathrm {~V}$
B) $3.0 \mathrm {~V}$
C) $2.0 \mathrm {~V}$
D) $1.6 \mathrm {~V}$
E) $2.6 \mathrm {~V}$

Question

For the circuit shown in the figure, $V = 20 \mathrm {~V} , C = 10 \mu \mathrm { F } , R = 0.80 \mathrm { M } \Omega$, and the battery is ideal. Initially the switch $\mathrm { S }$ is open and the capacitor is uncharged. The switch is then closed at time $t =$ $0.00 \mathrm {~s}$. What is the potential difference across the resistor $20 \mathrm {~s}$ after closing the switch?

A) $2.3 \mathrm {~V}$ 
B) $3.0 \mathrm {~V}$ 
C) $2.0 \mathrm {~V}$ 
D) $1.6 \mathrm {~V}$ 
E) $2.6 \mathrm {~V}$

Quizplus · Accepted Answer

The Answer of For the circuit shown in the figure, $V = 20 \mathrm {~V} , C = 10 \mu \mathrm { F } , R = 0.80 \mathrm { M } \Omega$, and the battery is ideal. Initially the switch $\mathrm { S }$ is open and the capacitor is uncharged. The switch is then closed at time $t =$ $0.00 \mathrm {~s}$. What is the potential difference across the resistor $20 \mathrm {~s}$ after closing the switch?

A) $2.3 \mathrm {~V}$ 
B) $3.0 \mathrm {~V}$ 
C) $2.0 \mathrm {~V}$ 
D) $1.6 \mathrm {~V}$ 
E) $2.6 \mathrm {~V}$

For the Circuit Shown in the Figure V=20 V,C=10μF,R=0.80MΩV = 20 \mathrm {~V} , C = 10 \mu \mathrm { F } , R = 0.80 \mathrm { M } \OmegaV=20 V,C=10μF,R=0.80MΩ

For the Circuit Shown in the Figure $V = 20 \mathrm {~V} , C = 10 \mu \mathrm { F } , R = 0.80 \mathrm { M } \Omega$