How much current will be flowing through a $57.0 - \mathrm { m }$ length of copper wire with radius $0.0$ mm if it is connected to a source supplying $62.0 \mathrm {~V}$ ? The resistivity of the metal is $1.68 \times 10 ^ { - 8 } \Omega \cdot \mathrm { m }$.
A) $0 \mathrm { nA }$
B) $0 \mathrm {~A}$
C) $0 \mathrm {~A}$.
D) $0 \times 10 ^ { 8 } \mathrm {~A}$

Question

Quizplus · Accepted Answer

The resistance of the wire is:$$R = \rho \frac{L}{A} = \rho \frac{L}{\pi r^2}$$where $\rho$ is the resistivity, $L$ is the length, $A$ is the cross-sectional area, and $r$ is the radius.Substituting the given values, we get:$$R = (1.68 \times 10^{-8} \Omega \cdot \mathrm{m}) \frac{57.0 \mathrm{m}}{\pi (0.05 \times 10^{-3} \mathrm{m})^2} = 2.14 \times 10^3 \Omega$$The current is then:$$I = \frac{V}{R} = \frac{62.0 \mathrm{V}}{2.14 \times 10^3 \Omega} = 0 \mathrm{A}$$

How Much Current Will Be Flowing Through A 57.0−m57.0 - \mathrm { m }57.0−m

How Much Current Will Be Flowing Through A $57.0 - \mathrm { m }$