A tiny particle with charge $+ 5.0 \mu \mathrm { C }$ is initially moving at $55 \mathrm {~m} / \mathrm { s }$. It is then accelerated through a potential difference of $500 \mathrm {~V}$. How much kinetic energy does this particle gain during the period of acceleration?

Question

Quizplus · Accepted Answer

The kinetic energy gained by the particle can be calculated using the formula $KE = qV$, where $q$ is the charge in coulombs and $V$ is the potential difference in volts. Converting the charge to coulombs ($5.0 \mu C = 5.0 \times 10^{-6} C$) and plugging in the values, we get $KE = 5.0 \times 10^{-6} C \times 500 V = 2.5 \times 10^{-3} J$.

A Tiny Particle with Charge +5.0μC+ 5.0 \mu \mathrm { C }+5.0μC

A Tiny Particle with Charge $+ 5.0 \mu \mathrm { C }$