A proton that is initially at rest is accelerated through an electric potential difference of magnitude $500 \mathrm {~V}$. How much kinetic energy does it gain? $\left( e = 1.60 \times 10 ^ { - 19 } \mathrm { C } \right)$

Question

Quizplus · Accepted Answer

The kinetic energy gained by the proton is equal to the charge of the proton multiplied by the potential difference it is accelerated through, which is $1.60 \times 10^{-19} \mathrm{C} \times 500 \mathrm{V} = 8.0 \times 10^{-17} \mathrm{J}$.

A Proton That Is Initially at Rest Is Accelerated Through 500 V500 \mathrm {~V}500 V

A Proton That Is Initially at Rest Is Accelerated Through $500 \mathrm {~V}$